Question 827277
<pre>
-4x+32y = -28

Find 3 points:

Let y = -1

-4x+32(-1) = -28
-4x-32 = -28
   -4x = 4
     x = -1

So one point is (-1,-1)

Let y = 0

-4x+32(0) = -28
      -4x = -28
        x = 7

So another point is (7,0)

Let y = 1

-4x+32(1) = -28
   -4x+32 = -28
      -4x = -60
        x = 15

So another point is (15,1) 

Plot those points:


{{{drawing(400,800/7,-3,18,-3,3,graph(400,800/7,-3,18,-3,3),
circle(15,1,0.15),circle(15,1,0.13),circle(15,1,0.11),circle(15,1,0.09),circle(15,1,0.07),circle(15,1,0.05),circle(15,1,0.03),circle(15,1,0.01),

circle(7,0,0.15),circle(7,0,0.13),circle(7,0,0.11),circle(7,0,0.09),circle(7,0,0.07),circle(7,0,0.05),circle(7,0,0.03),circle(7,0,0.01),


circle(-1,-1,0.15),circle(-1,-1,0.13),circle(-1,-1,0.11),circle(-1,-1,0.09),circle(-1,-1,0.07),circle(-1,-1,0.05),circle(-1,-1,0.03),circle(-1,-1,0.01) )}}}

Draw the line through those three points:

{{{drawing(400,800/7,-3,18,-3,3,graph(400,800/7,-3,18,-3,3),
circle(15,1,0.15),circle(15,1,0.13),circle(15,1,0.11),circle(15,1,0.09),circle(15,1,0.07),circle(15,1,0.05),circle(15,1,0.03),circle(15,1,0.01),
line(23,2,-17,-3),
circle(7,0,0.15),circle(7,0,0.13),circle(7,0,0.11),circle(7,0,0.09),circle(7,0,0.07),circle(7,0,0.05),circle(7,0,0.03),circle(7,0,0.01),


circle(-1,-1,0.15),circle(-1,-1,0.13),circle(-1,-1,0.11),circle(-1,-1,0.09),circle(-1,-1,0.07),circle(-1,-1,0.05),circle(-1,-1,0.03),circle(-1,-1,0.01) )}}}

Edwin</pre>