Question 827250
x = first integer
x + 1 = second integer
x + 2 = third integer

The product of the two smallest = five times the largest less 5
(x)(x + 1) = 5(x+2) - 5
x^2 + x = 5x + 10 - 5
x^2 + x = 5x + 5
add -5x -5 to each side.
x^2 -4x -5 = 0
factor
(x - 5)(x + 1) = 0
So x = 5 or x = -1
Assuming we want positive integers,
the three integers are 5, 6 and 7
Let's check by substituting in (x)(x + 1) = 5(x+2) - 5
(5)(5+1) =? 5(5+2) - 5
(5)(6) =? 5(7) - 5
 30 =? 35 - 5
 30 = 30