Question 827154
all these are...are puzzles waiting to be solved
Sum and more than=adding
two digit number=## ex:(11, 35, 99, ...)
adding the digits together looks like: 1+1=2 for 11, 3+5=8 for 35, 9+9=18 for 99
these can also be viewed as variables for example say  xy=35 where x=3 and y=5 but if 3 where to be multiplied by 5 you don't get 35. so what this really looks like is 3*10+5=35  {{{highlight(10x+y)=35}}}   , and swapping positions is simply 35 to 53
with this in mind lets start the problem
we have numbers 
xy where {{{x+y=7}}} 
yx where {{{10y+x=27+10x+y}}}
now you have 2 equations so I'll solve for x first and substitute it in 2nd equation
{{{x=7-y}}}
{{{10y+(7-y)=27+10(7-y)+y}}}
distribute the 10
{{{10y+7-y=27+70-10y+y}}}
add like terms
{{{9y+7=97-9y}}}
add 9y to both sides and subtract 7 from both sides
{{{18y=90}}}
divide by 18
{{{y=5}}}
now simply solve for x by substituting in 5 for y
{{{x=7-(5)}}}
{{{x=2}}}
the original number should be{{{highlight_green(25)}}}
Lets check
{{{25+27=52}}}
{{{52=52}}}
this is correct