<PRE><B>Question 826928</B>
The sum of 4 consecutive odd integers exceeds twice the largest by 22. find the sum of the 4 numbers
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1st: 2x-3
2nd: 2x-1
3rd: 2x+1
4th: 2x+3
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Equation:
8x = 2(2x+3) + 22
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8x = 4x+28
4x = 28
x = 7
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Sum = 8x = 8*7 = 56
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Cheers,
Stan H.
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