Question 826760


{{{4x+4y=24 }}}....eq.1
{{{y=6x+20}}}....eq.2
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{{{4x+4y=24 }}}....eq.1.............substitute {{{y}}} from eq.2

{{{4x+4(6x+20)=24 }}}..........solve for {{{x}}}

{{{4x+24x+80=24 }}}

{{{28x=24-80 }}}

{{{28x=-56 }}}

{{{x=-56/28 }}}

{{{highlight(x=-2) }}}

now, go back to eq.2 and find {{{y}}}

{{{y=6x+20}}}....eq.2.........plug in value of {{{x}}} 

{{{y=6(-2)+20}}}

{{{y=-12+20}}}

{{{highlight(y=8)}}}