Question 826048
{{{3^(8-x) = 27^(2-x)}}}
Rework the right hand side.
{{{3^(8-x) = (3^3)^(2-x)}}}
For the next line, in general {{{(a^n)^m = a^(n*m)}}}
{{{3^(8-x) = (3)^(3*(2-x))}}}
{{{3^(8-x) = 3^((6-3x))}}}
Now we know 8 - x = 6 - 3x
Add 3x to each side.
 8 + 2x = 6
Subtract 8 from each side.
  2x = -2
So x = -1