Question 825977
Numbers m and n.
{{{m+n=(n-m)+12}}}, assuming n>m.
and 
{{{mn=102}}}


{{{m+n=n-m+12}}}
{{{2m=12}}}
{{{highlight(m=6)}}}


{{{mn=102}}}
{{{(6)n=102}}}
{{{n=102/6}}}
{{{highlight(n=17)}}}