Question 826011
 The cable for a suspension bridge is modeled by the equation 
h(x) = (1/800)(x − 200)^2 + 30
{{{graph(400,400,-500,1000,-10,250,(1/800)(x-200)^2+30)}}}
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where h metres is the distance above the base of the bridge 
and x metres is the distance from the left side of the bridge.
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Determine the turning point of the graph of the equation.
Vertex:: (200,30/800) = (200,0.0375) 
Determine the suitable values of x. [0,400]
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Note: h(0) = 80 ft.
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Determine the range of values of h.[0.0375,80] 
What distance does the cable span?:: 400 ft 
What is the closest distance of the cable from the base of the bridge?:: 0.0375' 
What is the greatest distance of the cable from the base of the bridge?:: 80'
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Cheers,
Stan H.
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