Question 826013
divide 95 into two parts such that one half of the first part exceeds one fifth of second part by 16 
-----
Using 2 variables::
Equations:
x + y = 95
(1/2)x - (1/5)y = 16

------
Modify:
x + y = 95
5x - 2y = 160
------
Modify:
5x + 5y = 475
5x - 2y = 160
---
Subtract and solve for "y":
7y = 315
y = 45 
----
The x = 95-45 = 50
------
Cheers,
Stan H.
-------------------