Question 825920
Jumping ahead a couple of steps,  let b = the base of the logarithm ( you did not indicate the base, so I might assume you mean base ten), {{{b^2=(x-1)(1-x)}}};


If base ten logs, then {{{(x-1)(x-1)(-1)=100}}}
{{{x^2-2x+1=100}}}
{{{x^2-2x-99=0}}}
{{{(x-11)(x+9)=0}}}
'
x=-9 or x=11