Question 825868
{{{(n^2+3n-4)/(n^2-16)}}}*{{{(n^2+3n-4)/(n^2-1)}}}
Everything will factor, the denominators are "difference of squares"
{{{((n+4)(n-1))/((n-4)(n+4))}}}*{{{((n+4)(n-1))/((n-1)(n+1))}}}
Cancel (n+4) and (n-1) leaving
{{{((n-1))/((n-4))}}}*{{{((n+4))/((n+1))}}}