Question 69848
A chemist needs 120 milliliters of a 59% solution, but has only 32% and 68% solutions available. Find how many milliliters of each, that should be mixed to get the desired solution.
:
Let x = amt of 68% solution
(120-x) = amt of 32% solution
:
The percent equation:
.68x + .32(120-x) = .59(120)
:
Multiply what's inside the brackets:
.68x + 38.4 - .32x = 70.8
:
.68x - .32x = 70.8 - 38.4
:
.36x = 32.4
:
x = 32.4/36
:
x = 90 milliliters of the 68% solution
:
I'll let you figure out how much 32% solutions is needed