Question 9897
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Arctan(1) + Arcsin(0) + Arccos{{{(sqrt(3)/2)}}}

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Arctan(1) = ? asks tan(?) = 1 ---> answer: 45° or {{{pi/4}}} radians

Arcsin(0) = ? asks sin(?) = 0 ---> answer: 0°  or 0 radians

Arccos{{{(sqrt(3)/2)}}} = ? asks cos(?) = {{{sqrt(3)/2}}} ---> answer: 30° or {{{pi/6}}} radians

So, if your answer is to be in degrees:

Arctan(1) + Arcsin(0) + Arccos{{{(sqrt(3)/2)}}} = 45° + 0° + 30° = 75°    

Or if your answer is to be in radians:

Arctan(1) + Arcsin(0) + Arccos{{{(sqrt(3)/2)}}} = {{{pi/4}}} + {{{"0"}}} + {{{pi/6}}} = {{{pi/4}}} + {{{pi/6}}} = {{{3pi/12}}} + {{{2pi/12}}} = {{{5pi/12}}}

Edwin</pre>