<PRE><B>Question 825837</B>
an aircraft flew 4 hours with the wind.  The return trip took 5 hours against the wind.  If the speed of the plane in still air is 168 mph more than the speed of the wind, find the wind speed and the speed of the plane in still air
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With wind DATA: time = 4 hrs ; rate = 168+w ; distance = r*t = 4(168+w) miles
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Against wind DATA: time = 5 hrs; rate= 168-w ; distance = 5(168-w) miles
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Equation:
4*168+4w = 5*168-5w
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9w = 168
w = 18 2/3 mph (wind speed)
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Cheers,
Stan H.
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