Question 69807

The slope-intercept form is y = mx + b in which m and b are two constants.

All you have to do is to rearrange the given equation so that it is in the form:

y = mx + b.

The first thing to notice is that in the equation you were given, the term containing x
is on the left side, but in the slope-intercept form it is on the right side.  So to move 
the term containing the x to the right side, you can add x to both sides.  Adding x 
on the left side has the effect of canceling out the -x.  And adding x on the right 
side puts an x on the right side. The resulting equation is now:
{{{5y = x + 15}}}
When you compare this equation with the slope-intercept form, you should see that the 
slope-intercept form has only y on the left side.  But your equation now has 5y on the left
side.  You need to divide the left side of your equation by 5 so that it just becomes
y.  But if you divide the left side by 5, you must also divide all the terms on the right
side by 5.  The division is:

{{{5y/5 = x/5 + 15/5}}}

When you do the division you get:

{{{ y = (1/5)x + 3}}}

Now you have it exactly in the slope-intercept form.  You have just y on the left
side and on the right side you have {{{m = 1/5}}} and {{{b = 3}}}

Hope this helps.