Question 825742
This is how you multiply {{{(n^2+2n+1)/(n-1)}}} and {{{(1)/(n^2+1)}}}

{{{(n^2+2n+1)/(n-1)*(1)/(n^2+1)}}}
{{{(n+1)(n+1)/(n-1)* 1/(n+1)(n-1)}}}
{{{(n+1)(n+1)/(n-1)(n+1)(n-1)}}}
{{{(n+1)/(n-1) (n-1)}}}
{{{(n+1)/(n^2-2n+1)}}}

Hope it helpss. :)