Question 825606
If parallel, then slope is the same as the given line. m=1 for both lines when expressed in slope-intercept form, y=mx+b.


The line containing H(2,2) is y=x+b, and we find by through substituting the given point which is on y=x+b.
'
b=y-x
b=2-2
b=0
The sought line intersects the origin.
The line in slope-intercept form is simply {{{y=x}}}


The point-slope form comes from using definition of slope.
{{{m=1=(y-2)/(x-2)}}}
{{{1*(x-2)=y-2}}}
and the rest follows...  but this form does not give you any great advantage, since for such line, you could say y-12=x-12, or any  {{{y-k=x-k}}}.


You can find the standard form equation on your own.