Question 825623
Line wanted would be like {{{3x+2y=c}}}, keeping with standard form.


Use the given coordinates of the point:  {{{3(-4)+2(20)=c}}};
{{{c=40-12}}}
{{{c=28}}}
Standard Form line is then {{{highlight(3x+2y=28)}}}.


Converting to slope-intercept form means solve for y:
{{{2y=-3x+28}}}
{{{highlight(y=-(3/2)x+14)}}}.


Use the definition of slope to find the point-slope form.
{{{highlight_green(-(3/2)=(y-20)/(x-(-4)))}}}, and simplify putting into the correct form.