Question 825614
1. For the simple harmonic motion described by the trigonometric function,
d(t) = (2/3)cos(30pI t)
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Find:: 
a)the maximum displacement:: amplitude = 2/3
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b) the frequency:: (2pi)/(30pi) = 1/15
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C) the least positive value of t for which d=0
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Solve (2/3)cos(30pI t) = 0
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cos(30pi t) = 0
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Since cos = 0 when the angle = pi/2
30pi t = pi/2
60t = 1
t = 1/60 radians
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Cheers,
Stan H.
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