Question 825613
<pre>
The above "tutor" should not be on here. 

Here is the graph of y=x²-6x+10 and the green line through x=3
is its axis of symmetry:

{{{drawing(2000/7,400,-2,8,-2,12,
green(line(3,-10,3,20)),
graph(2000/7,400,-2,8,-2,12, x^2-6x+10) )}}}

So its turning point is found when we substitute 3 for x in

 y = x²-6x+10
 y = 3²-6(3)+10
 y = 9-18+10
 y = -9+10
 y = 1

So the turning point is where the green line x=3 crosses the 
parabola graph. It's x-coordinate is 3 and its y-coordinate
is 1.

So the turning point is (3,1)

You were just asked for the y-coordinate, so it's 1.

Edwin</pre>