Question 825270
Roots of a quadratic equation given, set-up (x-a)(x-c)=0, like this:


{{{(x+7/2)(x-2/3)=0}}}, giving you the roots you want;
and to have coefficients to be integers, looking at the 2 and 3 denominators, use factor of 6:


{{{highlight(6(x+7/2)(x-2/3)=0)}}}.


You could multiply completely to check the result as general form.