<PRE><B>Question 825253</B>
The legs of a right triangle have lengths (in units) x+2 and x+6. The hypotenuse has lengths (in units) 2x. Find the perimeter of the triangle.
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Use Pythagoras to get:
(2x)^2 = (x+2)^2 + (x+6)^2
4x^2 = x^2 +4x+4 + x^2 + 12x + 36
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2x^2 = 16x+40
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x^2 - 8x - 20 = 0
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Factor:
(x-10)(x+2) = 0
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Positive solution:
x = 10
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hypotenuse = 2x = 20
leg = x+2 = 12
leg = x+6 = 16
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Cheers,
Stan H.
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