Question 825059
We are looking for factors which are the 0's of 2x^3-5x^2-4x+3
I start by looking for rational roots and of course, 1 or -1 is worth checking first
if x = 1, we get 2 -5 -4 +3 = -4 so 1 is not a 0
if x = -1, we get -2 -5 +4 +3 = 0 so -1 is a 0 and x+1 is a factor.  Now use synthetic division
-1 | 2  -5  -4  3  |
   |    -2   7 -3  |            |
   | 2  -7   3  0  |
This leaves us with the smaller polynomial 2x^2 -7x +3 and we can factor this smaller polynomial into (2x-1) * (x-3),  therefore the complete factorization of
2x^3-5x^2-4x+3 is (x+1)*(2x-1)*(x-3)