Question 825031
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2.5x + 3.7y = 13.365
8.2x - 1.5y = 7.02
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solve the system by the matrix method:
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solution by the matrix method:
x = 1.35
y = 2.7
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system matrix
2.5 3.7
8.2 -1.5
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inverse of system matrix
0.044001173 0.10853623
0.24053975 -0.073335289
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determinant of system matrix = -34.09
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now solve the system by substitution:
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2.5x + 3.7y = 13.365
3.7y = 13.365 - 2.5x
y = (13.365/3.7) - (2.5/3.7)x
y = (3.612162162162162) - (0.675675675675676)x
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let:
A = 3.612162162162162
B = -0.675675675675676
y = A + Bx
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8.2x - 1.5y = 7.02
8.2x - 1.5(A + Bx) = 7.02
8.2x - 1.5(A) - 1.5(B)x = 7.02
8.2x - 1.5(B)x = 7.02 + 1.5(A)
(8.2 - 1.5(B))x = (7.02 + 1.5(A))
x = (7.02 + 1.5(A))/(8.2 - 1.5(B))
x = (7.02 + 1.5*(3.612162162162162))/(8.2 - 1.5*(-0.675675675675676))
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x = 1.35
y = A + Bx
y = A + (B)*(1.35)
y = 3.612162162162162 + (-0.675675675675676)*(1.35)
y = 2.67
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solution by the substitution method:
x = 1.35
y = 2.7
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NOTE: matrix method and substitution method solutions agree.
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