<PRE><B>Question 824982</B>
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x = length
y = width
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x = 3y
(x + 2)(y + 2) = 32
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(x + 2)(y + 2) = 32
(3y + 2)(y + 2) = 32
3yy + 6y + 2y + 4 = 32
3yy + 8y - 28 = 0
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the above quadratic equation is in standard form, with a=3, b=8, and c=-28
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
3 8 -28
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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this quadratic has two real roots (the x-intercepts), which are:
y = 2
y = -4.66666667
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the negative root does not fit the problem statement, so use the positive root
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answer:
x = length = 6 cm
y = width = 2 cm
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Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
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Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
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Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php</PRE>