Question 824790
Solve the exponential equation
a)(2^x)^2 = 16(2)^x
{{{2^(2x) = 16*2^x}}}
{{{2^(2x)/2^x}}} = 16
{{{2^(2x-x)}}} = 16
{{{2^x}}} = 16
16 is the 4th power of 2, therefore
x = 4