Question 824833
Let {{{ d }}} = the distance he traveled in miles before noon
{{{ 275 - d }}} = the distance he traveled in miles after noon
------------
Let {{{ t }}} = the time in hours he traveled before noon
{{{ 8 - t }}} = the time in hours he traveled after noon
---------------------------------------------
Equation before noon:
(1) {{{ d = 40t }}}
Equation after noon:
(2) {{{ 275 - d = 25*( 8 - t ) }}}
--------------------------
By substitution:
(2) {{{ 275 - 40t = 200 - 25t }}}
(2) {{{ 15t = 75 }}}
(2) {{{ t = 5 }}}
and
{{{ 8 - 5 = 3 }}}
His trip started at 12:00 minus 5 hrs = 3:00 AM
It ended at 12:00 plus 3 hrs = 3:00 pm