Question 824626
{{{ (2x^2 + xy -y^2) + 2x - y }}}
This can be factored using factoring by grouping. And the expression already has the first group (in the parentheses). So we group the rest of the expression...
{{{ (2x^2 + xy -y^2) + (2x - y) }}}
... and factor each group. The first group is a trinomial which factors. The second group can only be factored by factoring out a 1 (or -1):
{{{ (2x-y)(x+y) + 1*(2x - y) }}}
As we can see, each group now has a common factor, 2x-y. So we can factor that out of each group:
{{{ (2x-y)((x+y) + 1) }}}
or just
{{{ (2x-y)(x+y + 1) }}}