Question 824517
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use a right triangle:
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a = 325 at 180 degrees (true north)
b = 40 at 90 degrees (true north)
h = (hypotenuse) is the airplane's velocity vector
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h = sqrt( a*a + b*b )
h = sqrt( 325*325 + 40*40 )
h = 327.452286600658795
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A = angle of h relative to a
tanA = opp/adj
tanA = 40/325
A = arctan( 40/325 )
A = 7.016501744722909 degrees (relative to a)
resultant angle = 180 - 7.016501744722909
resultant angle = 172.983498255277084
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answer:
the resultant velocity of the airplane is:
327.5 mph at 173 degrees (true north)
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