Question 9223
From the first equation 2x+3y = 1, we get {{{y = (1-2x)/3}}}. Substitute it into the second equation

{{{x*(x+(1-2x)/3) = 10}}}

*[invoke explain_simplification "x*(x+(1-2x)/3) = 10"]

x=5,-6

Substitute it into the first equation {{{y = (1-2x)/3}}}

x=5:

*[invoke substitution "(1-2x)/3", "x", 5]

x=-6:
*[invoke substitution "(1-2x)/3", "x", -6]

Answer: {{{system( x=5, y=-3)}}} and {{{system( x=-6, y=13/3) }}}