Question 824337
a) C+K+J=290,000
b) K=2/3C  ?
c) J=3/4C
replace  (b) and (c) in (a)
C+2/3C+3/4C=290,000
(12C+8C+9C)/12=290,000
multiply by 12
12C+8C+9C=(290,000)(12)
29C=290,000*12
divide by 29
C=290,000*12/29
d) C=120,000
replace (d) on (b)
K=2/3C
K=2*120,000/3
K=80,000