Question 824229
Solve the following equation for X: 
logx + log(X-1)= Log(4x)
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log[x(x-1)] = log(4x)
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x^2-x = 4x
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x^2-5x = 0
Factor:
x(x-5) = 0
x = 0 (extraneous)
x = 5 (only answer)
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Cheers,
Stan H.
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Answer options
a)X=0,5
B)X=1/4log(x-1)
C)X=5
D)there are no solutions