Question 824224
1)consider a set of 900 of data values with a mean of 24 and standard deviation of 4.0
a)how many values are larger than 27.00
z(27) = (27-24)/4 = 3/4
P(x > 27) = P(z > 3/4) = 0.2266
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Answer: 0.2266*900 = 204
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b) how many values are btween 23.00 and 28.00
z(28) = (28-24) = 4/4 = 1
P(27 < x < 28) = P(3/4 < z < 1) = normalcdf(3/4 , 1) = 0.06
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Ans: 0.06*900 = 54
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Cheers,
Stan H.
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