Question 69678
Subtract. Write your answer in simplest form. 
{{{((y-2)/(y+3))-((y)/(2y+6))}}}  rewrite as follows:

{{{((y-2)/(y+3))-((y)/2(y+3))}}} 
The LCM is {{{2(y+3)}}} So we'll will multiply both terms by {{{2(y+3)/2(y+3)}}} to get a common denominator and we have:

{{{(2(y-2)-y)/2(y+3)}}} and this equals

{{{(2y-4-y)/2(y+3)}}}  which equals

{{{(y-4)/2(y+3)}}}------------------ans

Hope this helps---ptaylor