Question 824035
{{{x^2-2sqrt( 6 )-5=0}}}
With an {{{x^2}}} term but no x term we can solve this with a square root. First we isolate the {{{x^2}}} by adding {{{2sqrt(6)}}} and 5 to each side:
{{{x^2=2sqrt( 6 )+5}}}
Now we do a square root of each side:
{{{sqrt(x^2)= 0 +- sqrt(2sqrt( 6 )+5)}}}
(Note: The zero is there because a flaw in algebra.com's formula software will not let me use a plus or minus symbol without a number in front. You do not need the zero.)
{{{x = 0 +- sqrt(2sqrt( 6 )+5)}}}