<PRE><B>Question 823863</B>
find all the missing parts of the triangle. given values for angles in terms of radians.
A=pi/6
B=3pi/12
a=2
b=?
C=?
c=?
***
A+B+C=&amp;#960;
C=&amp;#960;-(A+B)=&amp;#960;-(3&amp;#960;/12+&amp;#960;/6)=&amp;#960;-(6&amp;#960;/24+4&amp;#960;/24)=&amp;#960;-10&amp;#960;/24=&amp;#960;-5&amp;#960;/12=7&amp;#960;/12
..
sinC=sin(7&amp;#960;/12)&amp;#8776;0.9659
sinB=sin(3&amp;#960;/12)=sin(&amp;#960;/4)=&amp;#8730;2/2
sinA=sin(&amp;#960;/6)=1/2
..
sinA/2=sinB/b
b=2sinB/sinA=(2&amp;#8730;2/2)/(1/2)=2&amp;#8730;2
..
sinA/2=sinC/c
c=2sinC/sinA==2*0.9659/(1/2)&amp;#8776;4.1412</PRE>