Question 69633
THE SLOPE OF A LINE THROUGH THESE TWO POINTS IS 
(Y2-Y2)/(X2-X1)
(65+25)/(50-30)
100/20
5 IS THE SLOPE (m)
NOW WE SUBSTITUTE ONE SET OF X & Y VALUES TO SOLVE FOR THR Y INTERCEPT(b) IN THE LINE EQUATION 
Y=mX+b
-25=5*30+b
-25=150+b
B=-25-150
b=-175 THUS THE EQUATRION FOR THIS LINE IS
Y=5X-175