Question 823651
The sum of three numbers is eighty. The larget number is ten more then twice the smallest number nand the middle number is five less than twice the smallest number. Find all the numbers
------------------
smallest: a
middle::  b
largest:  c
-------------
Equations:
a + b + c = 80
c = 2a+10
b = 2a-5
--------------
Substitute and solve for "a":
a + (2a-5) + (2a+10) = 80
5a + 5 = 80
a = 15
b = 2a-5 = 25
c = 2a+10 = 40
===================
Cheers,
Stan H.
===================