Question 823433
suppose theta is an angle in standard position whose terminal side lies in quadrant IV. If sin of theta = -4/5 find the value for cot theta
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In quadrant IV sin<0, cos>0, cot<0
{{{cos(x)=sqrt(1-sin^2(x))=sqrt(1-(16/25))=sqrt(9/25)=3/5}}}
note: a shortcut method is to recognize you are working with a (3-4-5)reference right triangle, then, cosx=3/5.
cotx=cosx/sinx=3/-4=-3/4