<PRE><B>Question 823471</B>
How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of a 20% antifreeze solution to get a mixture that is 50% antifreeze? Use the six-step method.
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Equation:
anti + anti = anti
0.60x + 0.20*80 = 0.50(x+80)
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Multiply thru by 100 to get:
60x + 20*80 = 50x + 50*80
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10x = 30*80
x = 3*80
x = 240 (amt. of 60% solution needed)
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Cheers,
Stan H.
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