Question 823449
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Hi,
Rules of Logarithms:
*[tex \large\ \ nlog_bx = log_b(x^n)]    | Applies to this question
*[tex \large\ \ log_bx + log_by = log_b(xy) ]  |Applies to this question
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]     
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
(7/3)logn(7y) + (2/5)logn(49y^2) 
 Now I know the first step is to put the fractions in front of the log into exponent form so you get: 
 {{{log(n,((7y)^(7/3))) + log(n,((49y^2)^(2/5)))}}}    | Applied Rule.  Good Work
{{{log(n,((7y)^(7/3)((7^2)(y^2))^(2/5)))}}}    | Applied Rule
Add  Exponents of Like terms to finish  |Note: {{{7/3 + 4/5 = 47/15}}}