Question 823447
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Hi,
Rules of Logarithms:
*[tex \large\ \ nlog_bx = log_b(x^n)]    | Apply to this question
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]     |Apply to this question
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
2ln x - 5ln c 
 {{{green( ln (x^2)  - ln (c^5))}}}    | Applied Rule
 {{{ green( ln (x^2/c^5))}}}           | Applied Rule