<PRE><B>Question 823413</B>
375 students scored 82.5 with a standard deviation of 7.5. How many scored between 75 and 90?
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Find the z-value of 75 and of 90.
Find the probability that z lies between those two z-values.
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Ans: normalcdf(75,90,82.5,7.5) = 0.6827
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Cheers,
Stan H.
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