Question 823381
-5      	x	+	3	y  	=	3				
Find the slope of this line										                                                                                                            
										
3	y  	=	5      	x	+	3    				
Divide by	3									
	y  	=	5/ 3	x	+	1    				
Compare this equation with y=mx+b,					m= slope & b= y intercept					
slope m =	5/3									
										
The slope of a line perpendicular to the above line will be the negative reciprocal										- 3/5
Because m1*m2 =-1										
The slope of the required line will be			- 3/5							
										
m=	- 3/5	,point	(	-8	,	-9	)			
Find b by plugging the values of m & the point in										
y=mx+b										
-9	=	24/ 5	+	b						
b=	-69/5									
m=	- 3/5									
The required equation is		y  	=	-  3/ 5	x	+	-69/ 5	

multiply by 5
5y=-3x-69
3x+5y=-69		
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