Question 69563
L has y-intercept (0, -3)and is parallel to the line with equation y= 2/3x + 1.
The slope intercept form of a line is {{{highlight(y=mx+b)}}}, where m=slope and (0,b)=y-intercept
The slope of y=2/3x+1 is m=2/3.
Parallel lines have the same slope, so L has a slope m=2/3 and a y-intercept (0,b)=(0,-3)
Plug those values into the slope intercept form and you have:
y=mx+b
y=2/3x+(-3)
{{{highlight(y=(2/3)x-3)}}}
Happy Calculating!!!!