<PRE><B>Question 823157</B>
&lt;pre&gt;
2x&lt;sup&gt;3&lt;/sup&gt;-3x&lt;sup&gt;2&lt;/sup&gt;+x&lt;sup&gt;5&lt;/sup&gt;

Arrange the terms in descending order of exponents of x:

x&lt;sup&gt;5&lt;/sup&gt;+2x&lt;sup&gt;3&lt;/sup&gt;-3x&lt;sup&gt;2&lt;/sup&gt;

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It can be factored as

x&lt;sup&gt;2&lt;/sup&gt;(x-1)(x&lt;sup&gt;2&lt;/sup&gt;+x+3)

but that is the factored form, not the standard form.

Edwin&lt;/pre&gt;</PRE>