Question 823135
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Hi,
Finding vertex form of:
h = -5t^2+20t+105      |Completing the Square
h = -5(t^2 - 4t)   + 105     |Note:   t^2 -4t + 4 = (t-2)^2 
h= -5(t-2)^2 + 20 + 105
h=  -5(t-2)^2 + 125   V(2,125)