Question 69479
{{{x^2 = 5x + 2}}}
{{{x^2-5x = cross(5x -5x)+2}}} Get the 5x term to the left side
{{{x^2-5x = 2}}}Take half of the 2nd coefficient and square it {{{(1/2*5)^2=25/4}}}
{{{x^2-5x+25/4 = 2+25/4}}} Add this value to both sides
General form of perfect square
{{{y=(x+-b)^2+k}}} To find value of b, take half of 2nd coefficient.
{{{(x-5/2)^2=8/4+25/4}}}
{{{(x-5/2)^2=33/4}}}
{{{(x-5/2)^2-33/4=0}}}
Answer: {{{y=(x-5/2)^2-33/4}}}
If you graph y=x^2 - 5x - 2 and y=(x-5/2)^2-33/4 together they should be the same graph, verifying the answer