Question 68359
{{{log_[b](x) + log_[b](y)= log_[b](x*y)}}}Use this identity to change left side
{{{log_[3](x+7) + log_[3](2)= log_[3](20)}}}Combine left side
{{{log_[3](2*(x+7))= log_[3](20)}}}Get rid of the log's by raising everything to base of 3 (ie undoing the log)
{{{cross(3)^((cross(log_[3])(2x+14)))= cross(3)^((cross(log_[3])(20)))}}}
{{{2x+14=20}}}Solve for x
{{{x=3}}}