Question 823049
 (2x+3)^2 = (2x-5)^2 +( x+7)^2
4x^2+12 x+9 = 5 x^2-6 x+74
x^2-18 x+65 = 0
(x-5)*(x-13)
x=5 x=13
13^2=5^2 +12^2
29^2=21^2+20^2